19x^2+78x+59=0

Solution for 19x^2+78x+59=0 equation:

19x^2+78x+59=0

a = 19; b = 78; c = +59;
Δ = b2-4ac
Δ = 782-4·19·59
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(78)-40}{2*19}=\frac{-118}{38}
=-3+2/19
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(78)+40}{2*19}=\frac{-38}{38}
=-1
$